I have set the 'contuinue shopping' button with my own background image (using jquery). The check boxes on the shopping cart have an onchange event which changes the background-color and removes my image. I have tried to unbind the event with <code>jQuery("input#remove_array").unbind();</code> I'm not sure if this is the correct usage as I relatively new to jquery but it seems like it would do the trick. I have also tried a number of alteration on this such as <code>jQuery("#remove_array").unbind();</code> <code>jQuery("input").unbind("change");</code>The list goes on. I tried a load of different statements - for a couple of fun filled hours on the firebug console;-)
It is this code on the check box that is causing the issue:<code>onchange="document.getElementById('btnUpdtCart').style.background='#FFFF99';"</code>All of the above refers to code put in to the checkout button (between the script tags) - the 'EJEJC_shown' function.
This has been resolved.The following code will remove the event:<code>jQuery("input:checkbox").attr("onchange" , "");</code>The "input:checkbox" targets all of the check boxes and "attr" manipulates the onchange attribute.
Thanks for posting this! I was having a similar issue and solved it by kind of hacking the code, so it's good to see a different and much cleaner way to solve this issue!Best,Amy Thttp://www.zippycart.com - Find and Compare Shopping Carts Online
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